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A sample of hydrogen chlorine was dissolved in water to make 250 cm³ of solution 25 cm³ of the solution required

A sample of hydrogen chlorine was dissolved in water to make 250 cm³ of solution 25 cm³ of the solution required 46 cm³ of 11.0 M sodium hydroxide for complete neutralization
i) Calculate the number of moles of hydrochloric acid in 25 cm³ of solution
ii) Determine the mass of hydrogen chloride that was dissolved to make 250 cm³ of solution (Cl = 35.5, H = 1.0)

Answers

i) HCL_(aq) + NaOH_(aq) $\rightarrow$ NaCl_(aq) + H₂O_l

Moles of NaOH = Moles of HCL

= $\frac{46 \times 11}{1000}$ = 0.506 moles

ii) Moles of HCL in 250cm³ = 0.506 $\times$ 10 = 5.06

R.M.M of HCL = 1 + 35.5 = 36.5

Mass of HCL = 5.06 $\times$ 36.5

= 184.69g

johnmulu answered the question on February 9, 2017 at 09:23

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