Volume of drop = volume of patch
Vm3 = A m2 $\times$ d
d = $\frac{Vm^3}{Am^2}$ = $\frac{V}{A}m$
johnmulu answered the question on February 9, 2017 at 10:02
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Date posted:
February 7, 2017
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Answers (1)
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Date posted:
February 7, 2017
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Date posted:
February 7, 2017
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Answers (1)
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February 7, 2017
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Date posted:
February 7, 2017
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Date posted:
February 7, 2017
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Date posted:
February 7, 2017
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February 7, 2017
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(Solved)
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Date posted:
February 7, 2017
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Answers (1)