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A light spiral extends by 4 mm when loaded with a weight W. The spring is connected in series with an identical spring

A light spiral extends by 4 mm when loaded with a weight W. The spring is connected in series with an identical spring. The combination is loaded with the weight W. Determine the extension of the combination.

Answers


John
K = $\frac{F}{e}$ = $\frac{w}{4 mm}$, k for series = $\frac{w}{4 mm}\div 2$

Total extension = $\frac{F}{k}$, e = $\frac{w}{w}$ x 4 x 2 = 8 mm
johnmulu answered the question on February 11, 2017 at 07:55

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