P = $\frac{V^2}{R}$
= 2500 = $\frac{240^2}{R}$,
R = 23.04$\Omega$
johnmulu answered the question on February 15, 2017 at 12:59
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An electric heater is connected to the mains supply. A fault in the mains reduces the supply potential slightly
(Solved)
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Date posted:
February 15, 2017
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Answers (1)
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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Answers (1)
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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Date posted:
February 15, 2017
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February 15, 2017
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February 14, 2017
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