P1 = 1.03 x 105, let the original volume be V1,
then final volume, V2 = $\frac{1}{8}V_1$
P1V1 = P2V2,
P2 = $\frac{P_1V_1}{V_2}$
= $\frac{(1.03\times 10^-5)V_1}{V1/8}$ = 8.24 x 105
johnmulu answered the question on February 18, 2017 at 08:30
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