Get premium membership and access questions with answers, video lessons as well as revision papers.
Got a question or eager to learn? Discover limitless learning on WhatsApp now - Start Now!

Light of frequency 7.5 x 1014Hz strikes a metal surface whose work function is 4.0 x 10-19 J. Determine the kinetic energy of the emitted photoelectrons.

      

Light of frequency 7.5 x 1014Hz strikes a metal surface whose work function is 4.0 x 10-19 J. Determine the kinetic energy of the emitted photoelectrons. (take planks constant h = 6.63 x 10-34Js)

  

Answers


John
hf = Wo + ke

Ke = hf - Wo = (6.63 x 10-34 x 7.5 x 1014) - 4.0 x 10-19

= 9.725 x 10-20 joules
johnmulu answered the question on February 21, 2017 at 13:03


Next: Define the term "threshold frequency" as used in photo electric emission.
Previous: A photo of ultraviolet light having energy E falls on a photo emissive surface whose work function is T. Write an expression for maximum kinetic energy of the resulting photoelectron in terms of E and T.

View More Physics Questions and Answers | Return to Questions Index


Learn High School English on YouTube

Related Questions