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A half-metre rule of mass 50g balances off-centre when a 20g mass is suspended at the 2 cm mark.

A half-metre rule of mass 50 g balances off-centre when a 20 g mass is suspended at the 2 cm mark. Determine the position of the pivot.

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Sum of clockwise moment = Sum of anti-clockwise moment

$\frac{20 \times 10}{1000}=\frac{23 - x}{1000} = \frac{50 \times 10}{1000} \times \frac{x}{100}$

$\frac{0.2}{100}(23 - x) = \frac{0.5x}{100}$

4.6 - 0.2x = 0.5x

x= 6.5 cm

raphael answered the question on January 14, 2017 at 14:14

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A half-metre rule of mass 50g balances off-centre when a 20g mass is suspended at the 2 cm mark.

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