Let the amount invested be sh. P
T =10 years
R = 12%
A = sh. 10000
But A = P + I
10000 = P + P x12% x10
10000 = 2.2P
Sh. 4545.45 = P
joseph rimiru answered the question on November 16, 2017 at 06:44
-
Calculate the rate of interest if sh. 9000 earns sh. 1000 after sh. 9000 earns sh. 1000 after 1 ½ years.
(Solved)
Calculate the rate of interest if sh. 9000 earns sh. 1000 after sh. 9000 earns sh. 1000 after 1 ½ years.
Date posted:
November 16, 2017
.
Answers (1)
-
Calculate the simple interest and the amount on sh. 8000 for 1 ½ years at 14% per annum.
(Solved)
Calculate the simple interest and the amount on sh. 8000 for 1 ½ years at 14% per annum.
Date posted:
November 16, 2017
.
Answers (1)
-
Solve for a in log (3a + 4) – log (3-a) =1
(Solved)
Solve for a in log (3a + 4) – log (3-a) =1
Date posted:
November 16, 2017
.
Answers (1)
-
Solve the following Log x = 3 log 2
(Solved)
Solve the following
Log x = 3 log 2
Date posted:
November 16, 2017
.
Answers (1)
-
Find without using tables if 2 + log 3 +log y = log 5 +1
(Solved)
Find without using tables if 2 + log 3 +log y = log 5 +1
Date posted:
November 16, 2017
.
Answers (1)
-
Solve for x in log x + log 6 = log 36
(Solved)
Solve for x in log x + log 6 = log 36
Date posted:
November 16, 2017
.
Answers (1)
-
Simplify (a) Log (a + 1) – log (a^2 -1) (b) Log x^4 +log x (c) Log 15 + log 3 – log...
(Solved)
Simplify
a. Log (a + 1) – log (a^2 -1)
b. Log x^4 +log x
c. Log 15 + log 3 – log 9
Date posted:
November 15, 2017
.
Answers (1)
-
Simplify (a) ½ log 9 –log 3 (b) 3 – 2 log 5 (c) Log 16 –log 8
(Solved)
Simplify
a. ½ log 9 –log 3
b. 3 – 2 log 5
c. Log 16 –log 8
Date posted:
November 15, 2017
.
Answers (1)
-
Simplify (a) Log 6 +log 4 (b) Log 4 – log 2 (c) Log 60 – log 20
(Solved)
Simplify
a. Log 6 +log 4
b. Log 4 – log 2
c. Log 60 – log 20
Date posted:
November 15, 2017
.
Answers (1)
-
Express in terms of x, y, and z given that log a =x, log b =y and log c = z (a) Log a^2b (b) Log...
(Solved)
Express in terms of x, y, and z given that log a =x, log b =y and log c = z
a. Log a^2b
b. Log (a/b)
c. Log (a^2b/c)
Date posted:
November 15, 2017
.
Answers (1)
-
State the three laws of logarithms.
(Solved)
State the three laws of logarithms.
Date posted:
November 15, 2017
.
Answers (1)
-
Express the following in terms log x, log y, and log z (a)Log xy (b) Log xyzc. Log (x/y)
(Solved)
Express the following in terms log x, log y, and log z
a. Log xy
b. Log xyz
c. Log (x/y)
Date posted:
November 15, 2017
.
Answers (1)
-
Write log 1000 – 2 log 50 as a logarithm of a single number
(Solved)
Write log 1000 – 2 log 50 as a logarithm of a single number
Date posted:
November 15, 2017
.
Answers (1)
-
Given that log 2= 0.3010 and log 3 =0.4771, simplify (a)Log 12 (b) Log 0.75 (c) Log 108
(Solved)
Given that log 2= 0.3010 and log 3 =0.4771, simplify
a. Log 12
b. Log 0.75
c. Log 108
Date posted:
November 15, 2017
.
Answers (1)
-
Express the following in logarithmic notationa. 8^2 =64 (b) 8^(1/3) =2 (c) 5^1 =5
(Solved)
Express the following in logarithmic notation
a. 8^2 =64
b. 8^(1/3) =2
c. 5^1 =5
Date posted:
November 15, 2017
.
Answers (1)
-
State the sine rule
(Solved)
State the sine rule
Date posted:
November 12, 2017
.
Answers (1)
-
An arc subtends an angle of 1.2 rad. If radius of circle is 15 cm, find the length of the arc.
(Solved)
An arc subtends an angle of 1.2 rad. If radius of circle is 15 cm, find the length of the arc.
Date posted:
November 12, 2017
.
Answers (1)
-
What is the length of an arc which subtends an angle of 0.9 radian at the centre of a circle of radius 20cm?
(Solved)
What is the length of an arc which subtends an angle of 0.9 radian at the centre of a circle of radius 20cm?
Date posted:
November 12, 2017
.
Answers (1)
-
Convert 135° into radian
(Solved)
Convert 135⁰ into radian
Date posted:
November 12, 2017
.
Answers (1)
-
Find the values of the sine, cosine, and tangent of the following angles 801°, 1031°, and 1250°.
(Solved)
Find the values of the sine, cosine, and tangent of the following angles 801⁰, 1031⁰, and 1250⁰.
Date posted:
November 12, 2017
.
Answers (1)