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If log k = 0.806 and y = 1.903, find the value of ky

If log k = 0.806 and y = 1.903, find the value of ky

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John
log k = 0.806 and y = 1.903

the value of ky is

0.806
+ 1.903
= 0.709

10o x antilog of 0.709

= 1 x 5.1168 = 5.12
johnmulu answered the question on March 6, 2017 at 11:57

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