let the test tube be y and beakers be x
now 3x+4y=560
2x+5y=490
2(3x+4y=560) = 6x+8y=1120
3(2x+5y=490) = 6x+15y=1470
subtract 6x-6x=0
8y-15y=-7y
1120-1470=-350
thus -7y=-350, find y, y=-350/-7, y=50,
replace the value y 3x+4(50)=560, 3x+200=560
collect like terms 3x=560-200, 3x=360, x=120
so, one test tube cost ksh.50 and one beaker costs ksh.120
neptune answered the question on November 21, 2017 at 07:05
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