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Figure 7 shows a non-uniform log of mass 100 kg balanced on the pivot by a 2 kg mass placed as shown.

Figure 7 shows a non-uniform log of mass 100 kg balanced on the pivot by a 2 kg mass placed as shown.
nowscan41920171002.jpg
Determine the distance of the centre of gravity of the log from the pivot.

Answers


John
Clockwise moment = Anticlockwise moment

100 x X = 2 x 2 = x = 0.04 m
johnmulu answered the question on April 18, 2017 at 13:33

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