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From the given data, we have
C0 = 0
C1 = 20mg/c.c. = 20/1000 = 0.02
C2 = 0.05 ppm = 0.05/106 = 5 x 10-8
q = 2 litres/minute = (2 x 10-3)/60
= 3.33 x 10-5 m3/s
From, Q = q(C1/C2 – 1)
= 3.33 x 10-5 [(0.02/5 x 10-8) – 1]
= 13.33 m3/s
jim items answered the question on April 9, 2018 at 18:29
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