Suppose an oil drop has a volume of 0.10 mm³ and forms a film with a radius of 10 cm. Calculate, the thickness of the...

Suppose an oil drop has a volume of 0.10 mm³ and forms a film with a radius of 10 cm. Calculate, the thickness of the oil film.

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Area of the film = ${\pi}r^2$ = 3.14 × 10 × 10 = 314 cm² = 31,400 mm²
Thickness of the oil film = volume / area, hence 0.10 / 31,400 = 3.0 × 10^-6 mm. (The
thickness of the oil film is called upper limit to the size of molecule because the molecule
cannot be bigger than the thickness of the oil film).

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Mutiso answered the question on October 11, 2018 at 18:41

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