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The angles of a quadrilateral are 3x^o, 2x^o, (x+54)^o and 2(x-7)^o. Find the smallest angle of the polygon.

Answers

Angles in a quadrilateral add up

to = 360^o

3x + 2x + x + 54 + 2x - 14 = 360

8x + 40 = 360

8x = 320; x = 40^o

the angles are

3x = 3(40) = 120^o

2x = 2 (40) = 120^o

x + 54 = 40 + 54 = 94^o

2(x - 7) = 2(40 - 7) = 2(33) = 66^o

the smallest angle is 66^o

johnmulu answered the question on June 9, 2017 at 12:02

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