Total coins=21
Total value=kshs 72
So let ;
Ksh 10 be x
Ksh 5 be 2x
Ksh 1 be y
since they say say there half as many kshs 10 coins as ksh 5
Then we say
2x+x+y=21
5(2x)+10(x)+1(y)=ksh 72
So the simultaneous equation will be
3x+y=21
20x+y=72
Solving as a simultaneous equation gives;
x=3
y=12
So the number of ksh 5 coins he has is 6
=6
kapoor answered the question on February 20, 2019 at 19:07
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