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A certain transformer steps down mains supply from 240V to 6C. There are 1200 turns in the primary circuit. A bulb of 36W is connected...

A certain transformer steps down mains supply from 240V to 6V. There are 1200 turns in the primary circuit. A bulb of 36W is connected to the secondary circuit. Given that the efficiency of the transformer is 100% determine:
a) The number of turns in the secondary circuit.
b) The current in the primary circuit.

Answers


Alice
a) 240/6=1200/y
y=(6x1200)÷240= 30turns
b) P=36W
V=240V
P=IpEp
36/240=(yx240)/240
y=0.15A

Alambi answered the question on February 6, 2019 at 09:08

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