(a) Initial vertical velocity = 0, a=10, S=4m
Therefore: S= ut + 1/2 gt2
4 = 0+5t2
t = 0.8944
Range (horizontal dist) = initial vel. (constant) x time
= 12 x 0.8944
= 10.73m
b) Initial and final horizontal velocities are equal =12m/s
Final vertical velocity = V= u + at
V= 0+10x0.8944
V= 8.944m/s
Wilfykil answered the question on March 26, 2019 at 09:04
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