1.26g of lead powder were dissolved in excess nitric (VI) acid to form lead nitrate solution. All the lead nitrate solution was reacted with sodium...

1.26g of lead powder were dissolved in excess nitric (VI) acid to form lead nitrate solution. All the lead nitrate solution was reacted with sodium sulphate solution.
(a) Write an ionic equation for the reaction between lead nitrate and sodium sulphate solutions.
(b) Determine the mass of lead salt formed in (a) above (Pb = 207, S = 32, O = 16).

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sharon kalunda answered the question on March 29, 2019 at 09:12

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