Sulphur (IV) oxide gas was bubbled into acidified potassium chromate (VI) and iron (III) sulphate solutions respectively.Explain the observations made in each case.

Sulphur (IV) oxide gas was bubbled into acidified potassium chromate (VI) and iron (III) sulphate solutions respectively.Explain the observations made in each case.
i) With potassium chromate (VI).
(ii) With iron (III) sulphate.

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(i) Orange potassium dichromate turns green due to reduction process // SO₂ is a reducing
agent where it reduces chromate (VI) ions to chromium (III) ions.
(ii) Brown iron (III) sulphate solution turns green due to reduction of
Fe³⁺ to Fe²⁺

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sharon kalunda answered the question on March 29, 2019 at 11:05

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