Describe the action of sulphuric (VI) acid on blue hydrated copper (II) sulphate.

Describe the action of sulphuric (VI) acid on blue hydrated copper (II) sulphate.

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(i). Procedure
- A few crystals of hydrated CuSO₄.5H₂O were put in a test tube and enough concentrated sulphuric (VI) acid added, to cover them completely.

(ii). Observation:
- Blue copper (II) sulphate pentahydrate crystals turn to white powder of anhydrous CuSO₄.



Explanations:
- Conc.H₂SO₄ has a very strong affinity for water and hence removes water of crystallization from crystals hence dehydrating them.

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Kavungya answered the question on April 29, 2019 at 12:39

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