When 8.53g of sodium nitrate were heated in an open test-tube, the mass of oxygen gas produced was 0.83 g . Given the equation of the reaction...

When 8.53g of sodium nitrate were heated in an open test-tube, the
mass of oxygen gas produced was 0.83 g . Given the equation of the
reaction as 2NaNO 3 (s) -> 2NaNO 2 (s) + O 2 (g)
Calculate the percentage of sodium nitrate that was converted to sodium
nitrite. (Na = 23.0, N = 14.0, O = 16.0)

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Kavungya answered the question on May 7, 2019 at 07:34

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