(x – 3) (AX2 +BX + C) = x3 – 7x – 6
AX3 + BX2 +CX – 3AX2 – 3BX – 3c = x3 – 7x – 6
A = 1
B – 3A = 0
B – 3 x 1 = 0
B = 3
-3c = -6
c = 2
Kavungya answered the question on June 18, 2019 at 11:37
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