A girl heats 5 kg of water to temperature of 80^oC. When she adds m kg of water at 15^oC the mixture attains...

A girl heats 5 kg of water to temperature of 80^oooC. Determine the value of m. (ignore heat changes due to the container)

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Heat gained 5(80 – 40) = m(40-15) Heat gained MCD ? ( 80- 40)
5(40) = 25m
Heat post MCD ? =m (40 – 15) MC 40 – 15
5(80-40) = 25 m
25m = 200 = m = 8 kg

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Githiari answered the question on September 18, 2017 at 17:11

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