Mary is four times as old as her last born John. In seven years time, the sum of their ages will be 59 years. Determine...

Mary is four times as old as her last born John. In seven years time, the sum of their ages will be 59 years. Determine their ages three years ago.

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Let John’s age be x
Mary’s age = 4x
7yrs time
(x +7) + (4x +7) = 59
5x +14 = 59
5x = 45
X =9
Mary’s = 9 x 4 = 36
John’s = 9years
3years ago
Mary = 33years
John = 6years

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sharon kalunda answered the question on August 16, 2019 at 14:39

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