(a) SO2(g) + NO2(g)----->SO3(g) + NO(g)
N + (-2 x 2) = 0 S + (-2 x 3) = N + (-2) = 0
S + (-2 x 4) = 4) N = 4 S = +6 N = +2
S = +4
O.N of S increased from +4 to +6 – Oxidation
O.N of N decreased from +4 to +2 – Reduction
(b) SO2
maurice.mutuku answered the question on September 16, 2019 at 06:12
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(Solved)
25cm³ of a solution of ammonium iron (II) sulphate (NH4)2 SO4. FeSO4 nH2O with concentration of 19.6g/l was titrated with
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Date posted:
September 16, 2019
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September 16, 2019
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September 16, 2019
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September 13, 2019
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September 13, 2019
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Date posted:
September 13, 2019
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September 13, 2019
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September 13, 2019
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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(Solved)
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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Date posted:
September 13, 2019
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(Solved)
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Date posted:
September 13, 2019
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Answers (1)
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September 13, 2019
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September 13, 2019
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(Solved)
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Date posted:
September 13, 2019
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Answers (1)