Trusted by millions of Kenyans
Study resources on Kenyaplex

Get ready-made curriculum aligned revision materials

Exam papers, notes, holiday assignments and topical questions – all aligned to the Kenyan curriculum.

Solve for q in the equation Sin (3? + 1200) = v3/2 in the range 0= ? = 1800

Solve for q in the equation Sin (3θ + 1200) = √3/2 in the range 0≤ θ ≤ 1800

Answers


Kavungya
fig8924920191535.png
Kavungya answered the question on September 24, 2019 at 12:36

Answer Attachments

Exams With Marking Schemes

Related Questions