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A simple pendulum was used by a student to determine the acceleration due to gravity, g, she obtained the following values: L = 80.0 cm,...

A simple pendulum was used by a student to determine the acceleration due to gravity, g, she obtained the following values: L = 80.0 cm, the period T was 1.9s. given that T=2π√(l/g) determine the value of g correct to two significant figures.

Answers

T=2pv(l/g)
T^2=(2p)^2(l/g)
1.92 =4p^2((.80)/g)
g= 8.75 m/s^2

joseph rimiru answered the question on October 6, 2017 at 20:06

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