When excess chlorine gas was bubbled into hot concentrated sodium hydroxide, the following reaction occurred

When excess chlorine gas was bubbled into hot concentrated sodium hydroxide, the following reaction occurred.

3Cl₂(g) + 6NaOH(aq) $\rightarrow$ NaClO₃(aq) + 5NaCl(aq) + 3H₂O(l)
In which product did chlorine undergo oxidation? Explain.

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Na ClO₃: Because oxidation number of chlorine increases from 0 to +5

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johnmulu answered the question on February 10, 2017 at 12:48

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