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A small object lies at the bottom of a water pond at a depth of 1.2 m. Given that the refractive index of water is 1.3

A small object lies at the bottom of a water pond at a depth of 1.2 m. Given that the refractive index of water is 1.3, Determine the apparent depth of the object. (Give your to 1 decimal place)

Answers


John
Apparent depth = $\frac{Real\;depth}{Refractive\;index}$

= $\frac{1.2}{1.3}$

= 0.9 m
johnmulu answered the question on February 14, 2017 at 05:50

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