An element P has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of P for 32 minutes and 10 seconds, 0.44 g of P were deposited at the cathode.

An element P has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of P for 32 minutes and 10 seconds, 0.44 g of P were deposited at the cathode. Determine the charge on an ion of P.
(1 Faraday = 96500 Coulombs)

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Q = It
= 0.5 x 1930 = 965 C

= 0.44 $\rightarrow$ 965C, 88g $\rightarrow$ $\frac{88\times 965}{0.44}$ = 193, 000 C,

Charge on P = $\frac{193, 000}{96, 500}$ = +2

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johnmulu answered the question on February 16, 2017 at 05:54

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