Get premium membership and access questions with answers, video lessons as well as revision papers.

An element P has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of P for 32 minutes and 10 seconds, 0.44 g of P were deposited at the cathode.

      

An element P has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of P for 32 minutes and 10 seconds, 0.44 g of P were deposited at the cathode. Determine the charge on an ion of P.
(1 Faraday = 96500 Coulombs)

  

Answers


John
Q = It
= 0.5 x 1930 = 965 C

= 0.44 $\rightarrow$ 965C, 88g $\rightarrow$ $\frac{88\times 965}{0.44}$ = 193, 000 C,

Charge on P = $\frac{193, 000}{96, 500}$ = +2
johnmulu answered the question on February 16, 2017 at 05:54


Next: When a current of 1.5 amperes was passed through a cell containing M3+ ions of metal M for 15 minutes, the mass of the cathode increases by 0.26 g. (1 Faraday = 96500 coulombs).
Previous: During purification of copper by electrolysis, 1.48 g of copper were deposited when current was passed through aqueous copper (II) sulphate for 2$\frac{1}{2}$ hours. Calculate the amount of current used. (Cu = 63.5; 1 F = 96500 C

View More Chemistry Questions and Answers | Return to Questions Index


Learn High School English on YouTube

Related Questions