Distance traveled by P from 8
-9.00 a.m.
= $\frac{70 km}{hr}$ x 1 hr = 70 km
Time taken by Q to overtake
P:t = $\frac{70}{110 \; - 70}$ = $\frac{70}{40}$
= $\frac{7}{4}$ hours
Distance traveled by Q before
overtaking P
= 110 x $\frac{7}{4}$ = 192.5 km
johnmulu answered the question on March 7, 2017 at 05:27
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Answers (1)
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