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In solving part (a)
First get the real volumes of water and alcohol
Water 40%*80=32ltrs
Alcohol 60%*80=48ltrs
Since only water was added the amount of alcohol didn't change bt only volume was dilute
48L=40%
XL=60%
Cross multiply and divide
(48L*60%)รท40% = 72L
X therefore is 40L
= 72-32=40L
IN SOLVING PART (b)
72L+30L=102L
Total volume=102L+48L=150L
%Alcohol=(48/150)*100=32%
IN SOLVING PART (c)
First get the volumes of water and alcohol in the 5L and 2L.
In 5L
Water=68% of 5L=3.4L
Alcohol=32% of 5L=1.6L
In 2L
Water=40% of 2=0.8L
Alcohol=60% of 2=1.2L
In the solution (7L)
Water= 3.4L+0.8L=4.2L
Alcohol= 1.6L+1.2L=3.8L
Calculation of ratios of water to alcohol
4.2:3.8
=42:38
Simplify
7:9
Charles W answered the question on December 26, 2017 at 09:33
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