a) The acceleration of the bullet.
For the bullet: u=0, v=200m/s, s=0.3m
v2=u2+2as
2002=0+(2)(0.3a)
a=40000/0.6 =5.667*24m/s2
b) The recoil velocity of the gun.
Total linear momentum before collision=total linear momentum after collision
(20*0)+(0.02*0)=(20*v)+(0.02*200)
v=-4/20= -0.2m/s.
Moraa orina answered the question on April 9, 2018 at 06:33
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