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A bullet of mass 2g travelling horizontally at 20m/s embeds itself in a block of wood of mass 990g suspended from a light inextensible...

A bullet of mass 2g travelling horizontally at 20m/s embeds itself in a block of wood of mass 990g
suspended from a light inextensible string so that it can swing freely. Find:
The velocity of the bullet and block immediately after collision.

Answers


Moraa
The velocity of the bullet and block immediately after collision.
(0.01*20)+(0.99*0)=(0.01+0.99)v
v=1/1 =1m/s
Moraa orina answered the question on April 9, 2018 at 06:39

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