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Figure 9 shows graph of velocity against time for a ball bearing released at the surface of viscous liquid.

Figure 9 shows graph of velocity against time for a ball bearing released at the surface of viscous liquid.
physics5152017122310.jpg
Explain the motion of the ball bearing for parts.
(i) OA
(ii) AB

Answers


John
(i) The weight of the ball bearing is greater than the up thrust and viscosity and the ball therefore accelerates downwards.

(ii) Ball moved with constant velocity when its weight was equal to sum of upward forces.
johnmulu answered the question on May 15, 2017 at 12:13

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