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On complete combustion of a hydrocarbon gas X, 1.32g of carbon (IV) oxide and 0.54g of water. Calculate the empirical formula of X

      

On complete combustion of a hydrocarbon gas X, 1.32g of carbon (IV) oxide and 0.54g of water. Calculate the empirical formula of X (C = 12.0, H = 1, O = 16.0)

  

Answers


Samuel
1 mole of CO2 weighs 44g
44g of CO2 contains 12g of c
? 1.32 of CO2 will contain 12/44×1.32
= 0.36g of C

1 mole of H2O weighs 18g
18g of H2O weigh 18g
? 0.54g of H2O will contain 2 ×0.54 = 0.06 of H
18

Element C H
Mass 0.36 0.06
Moles 0.36 0.06
12 1
: 2

Empirical form = CH2

Lywascomputers answered the question on August 19, 2018 at 18:24


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