2NaOH + H2X Na2X(aq) + H2O(l)
Mole ratio 2 : 1
100cm3 of NaOH contained 0.2 moles
? No. of moles of a dibasic acid and reacting 0.008 x ½ = 0.004 moles
0.004 moles weigh 0.2g
? 1 mole will weigh (0.2)/(0.004)
= 50g
(0.2)/RMM=0.004
? RM = (0.2)/(0.004) = 50g
Lywascomputers answered the question on August 19, 2018 at 18:16
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