A drop of olive oil, whose volume is 0.12 mm³, was placed on a surface of clean water.The oil spread and formed a patch of...

A drop of olive oil, whose volume is 0.12 mm³, was placed on a surface of clean water.
The oil spread and formed a patch of area 6.0 × 10⁴ mm². Estimate the size of the olive oil.

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Volume = 0.12 mm³
Area of the oil patch = 6.0 × 104 mm²
Volume = area × thickness of the patch, therefore
Thickness of the oil patch = volume / area
= 0.12 / 6.0 × 10⁴ = 2.0 × 10^-6 mm or 2.0 × 10^-9 m

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Mutiso answered the question on October 11, 2018 at 18:33

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