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A uniform rod is 1.0 m long weighs 5 N. It is supported horizontally at one end by a spring and the other end rests...

A uniform rod is 1.0 m long weighs 5 N. It is supported horizontally at one end by a spring and the other end rests on a table as shown below. A mass of 2kg is hung from the rod as shown; determine,
a) Reading of the spring balance
b) Reaction force, F, from the table.
spring12102018.jpg

Answers

Mutiso
a) The 2kg mass and the weight of the rod (5 N) gives clockwise moment while the spring balance provides anticlockwise moments.
Clockwise moments = (2 × 10) × 0.4 + (5 × 0.5) = 10.5 Nm.
Anticlockwise moments = S × 1 (reading of the spring balance)
1S = 10.5, hence S = 10.5 N.
b) Upward forces = downward forces Downward forces
= (2 × 10) + 5 = 25 N
Therefore F+ 10.5 = 25, hence F = 14.5 N.
Mutiso answered the question on October 12, 2018 at 06:09

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