A uniform rod is 1.0 m long weighs 5 N. It is supported horizontally at one end by a spring and the other end rests...

A uniform rod is 1.0 m long weighs 5 N. It is supported horizontally at one end by a spring and the other end rests on a table as shown below. A mass of 2kg is hung from the rod as shown; determine,
a) Reading of the spring balance
b) Reaction force, F, from the table.

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a) The 2kg mass and the weight of the rod (5 N) gives clockwise moment while the spring balance provides anticlockwise moments.
Clockwise moments = (2 × 10) × 0.4 + (5 × 0.5) = 10.5 Nm.
Anticlockwise moments = S × 1 (reading of the spring balance)
1S = 10.5, hence S = 10.5 N.
b) Upward forces = downward forces Downward forces
= (2 × 10) + 5 = 25 N
Therefore F+ 10.5 = 25, hence F = 14.5 N.

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Mutiso answered the question on October 12, 2018 at 06:09

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