The 1^st, 2^nd and 3^rd ionization energies in KJ/Mol of elements G and R are given below.

The 1^st, 2^nd and 3^rd ionization energies in KJ/Mol of elements G and R are given below.

(i) Define the term 1st ionization energy.
(ii) Apart from the decrease in energy levels, explain the big difference between the 1^st and 2^nd ionization energies.
(iii) Calculate the amount of energy for the process:

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(i) Energy required by an element to lose one electron in its outermost energy level in the gases state.
(ii) After losing the first electron the remaining electrons are firmly attracted by same number of protons hence require more energy for the second electron to be lost.
(iii) 420 + 3100 + 4800
= 8320KJ

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sharon kalunda answered the question on March 27, 2019 at 08:13

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