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In the figure below x=30cm, y=6cm, effort E=60N, A1=4cm2 and A2=12cm2.

In the figure below x=30cm, y=6cm, effort E=60N, A1=4cm2 and A2=12cm2.
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Calculate:
a) The force F exerted on the liquid at A1.
b) The velocity ratio of the system.
c) The maximum load that can be raised by the system.

Answers

sharon
a)By the principle of moments;
60Nx30cm= Fx6cm
F= (60x30)/6= 300N.

b)V.R of the lever system= effort arm/load arm =30cm/6cm= 5
V.R of the hydraulic system= area of load piston/area of effort piston= 12cm2/4cm2= 3
Therefore, the combined V.R= 5x3= 15.

c)Pressure at A1= Pressure at A2
300N/4cm2 =L/12cm2
L= (300*12)/4 =900N.
sharon kalunda answered the question on April 23, 2019 at 11:51

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