0.63g of lead powder were dissolved in excess nitric acid to form lead nitrate solution. All the lead nitrate solution was reacted with sodium sulphate solution. a)Write...

0.63g of lead powder were dissolved in excess nitric acid to form lead nitrate
solution. All the lead nitrate solution was reacted with sodium sulphate solution.
a)Write an ionic equation for the reaction between lead nitrate and sodium
sulphate solutions.
b) Determine the mass of the lead salt formed in (a) above.
(Pb = 207, S = 32.0 = 16)

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Kavungya answered the question on June 22, 2019 at 06:47

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