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Solve for x and y in the following pair of simultaneous equations xy=80 logx-2logy=1

Solve for x and y in the following pair of simultaneous equations
xy=80
logx-2logy=1

Answers

Kevin
In equation [1],xy=80,
make x the subject;x=80/y
In equation[2],logx-2logy;
removing log sign we have;
x/[y]squared=1.
but x=80/y
Therefore;80/y divide by [y] squared=1
this gives us ;80/y cubed =1
Hence [y]cubed =80
y=4.3089
If x=80/y then x =80/4.3089
x=18.566
Kevinsenzoochieng answered the question on July 9, 2019 at 13:48

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