5.0g of calcium carbonate were allowed to react with 25cm³ of 1.0M hydrochloric acid until there was no further reaction. Calculate the mass of calcium...

5.0g of calcium carbonate were allowed to react with 25cm³ of 1.0M hydrochloric acid until
there was no further reaction. Calculate the mass of calcium carbonate that remained
unreacted(Ca = 40, C = 12, O = 16).

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CaCO₃ + 2HCl (aq)---------> CaCl₂ (aq) + H₂O(l) + C0₂(g)
5.0g 25cm^3 1.0M
Moles of HCl =(25x 1.0)/1000= 0.025 moles
Moles of CaCO₃ =0.025/2
= 0.0125 moles
mass of calcium carbonate reacted = 0.125 x 100
= 1.25g Mass
mass of CaCO₃ un-reacted = 5.00 – 1.25
= 3.75g

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Githiari answered the question on September 18, 2017 at 07:19

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