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(i)Heat lost=mLv+mc(100-T)
H=(0.003×2260000)+
(0.003×4200[100-T])
H=6780+1260-12.6T
(ii)Heat gained=Mc(T-10)
H=0.4×4200(T-10)
H=1680T-16800
(iii) 1680T-16800=6780+1260-12.6T
1692.6T=24840
T= 14.68°C
jacktonenzoya answered the question on August 29, 2019 at 06:53
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