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In an experiment to determine solubility of sodium chloride, 10.0 cm3 of a saturated solution of sodium chloride weighing 10.70g were placed in a volumetric...

      

In an experiment to determine solubility of sodium chloride, 10.0 cm3 of a saturated solution of sodium chloride weighing 10.70g were placed in a volumetric flask and diluted to a total of 500cm3. 25.0 cm3 of the diluted solution of sodium chloride reacted completely with 24.0 cm3 of 0.1M silver nitrate solution.
Q1910252019923.png
I. Calculate;
(i) Moles of silver nitrate in 24.0 cm3 of solution.
(ii) Moles of NaCl in 25.0 cm3 of solution.
(iii) Moles of NaCl in 500 cm3 of solution.
(iv) Mass of NaCl in 10.0 cm3 of saturated sodium chloride (Na = 23, Cl = 35.5)
(v) Mass of water in 10.0cm3 of saturated solution.
(vi) The solubility of NaCl in g/100g of waters.

  

Answers


Maurice
Q1910252019931.png
25 cm3
= 0.048 moles
Q1910252019934.png


maurice.mutuku answered the question on October 25, 2019 at 06:35


Next: Calculate the solubility of salt given that 15g of the salt can saturate 25cm3 of water
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