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Solve for y in the equation 2sin²y - 1 = Cos² y + sin y. For values of 0° = y = 360°.

Solve for y in the equation 2sin²y - 1 = Cos² y + sin y. For values of 0° ≤ y ≤ 360°.

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Kavungya
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Kavungya answered the question on November 7, 2019 at 05:50

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