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Solve the equation log 3 + log (4x + 4) = 1 + log (2x – 2).

Solve the equation log 3 + log (4x + 4) = 1 + log (2x – 2).

Answers


Kavungya
Log [3( 4x + 4)] = log 10 + log (2x - 2)
Log (12x + 12) = log (2x -20)
12 x + 12 = 20x – 20
x = 32
Kavungya answered the question on November 15, 2019 at 05:11

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