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In the triangle ABC below AB = 3b and AC = 2c. BX = 4/13c - 30/13b. Point M divides BC in the ratio 2:3....

In the triangle ABC below AB = 3b and AC = 2c. BX = 4/13c - 30/13b. Point M divides BC in the ratio 2:3. Lines BX has been protected to meet AC at point N,

a)Find the following vector in terms of b and c
i) AX (
ii) AM
b) Prove that points A, X and M are collinear and state the ratio in which X divides AM
c) Given that BX:XN = 10:3, find the ratio in which N divides AC

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Kavungya answered the question on November 15, 2019 at 09:53

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