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Find the centre and the radius of a circle whose equation is x² + y² + 6y - 8x - 2y = 0.

Find the centre and the radius of a circle whose equation is x² + y² + 6y − 8x − 2y = 0.

Answers

X² - 8x + 16 + y² + 6y + a = 24 + 16 + 9
(x-4)² + (y+3)²=49
Center (4,-3)radius 7

Kavungya answered the question on November 18, 2019 at 13:57

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